LMNP is a rhombus, HJP and MJN are straight lines. If MJ = JP, ∠JPN = 15° and ∠KMN = 36°, find
- ∠JNP
- ∠KHJ
(a)
∠JNP
= 87° - 15°
= 72° (Exterior angle of a triangle)
(b)
∠MHJ
= 87° - 36°
= 51° (Exterior angle of a triangle)
∠KHJ
= 180° - 51°
= 129° (Angles on a straight line)
Answer(s): (a) 72°; (b) 129°