KLMN is a rhombus, GHN and LHM are straight lines. If LH = HN, ∠HNM = 21° and ∠JLM = 26°, find
- ∠HMN
- ∠JGH
(a)
∠HMN
= 82° - 21°
= 61° (Exterior angle of a triangle)
(b)
∠LGH
= 82° - 26°
= 56° (Exterior angle of a triangle)
∠JGH
= 180° - 56°
= 124° (Angles on a straight line)
Answer(s): (a) 61°; (b) 124°