FGHJ is a rhombus, CDJ and GDH are straight lines. If GD = DJ, ∠DJH = 17° and ∠EGH = 33°, find
- ∠DHJ
- ∠ECD
(a)
∠DHJ
= 82° - 17°
= 65° (Exterior angle of a triangle)
(b)
∠GCD
= 82° - 33°
= 49° (Exterior angle of a triangle)
∠ECD
= 180° - 49°
= 131° (Angles on a straight line)
Answer(s): (a) 65°; (b) 131°