FGHJ is a rhombus, CDJ and GDH are straight lines. If GD = DJ, ∠DJH = 20° and ∠EGH = 36°, find
- ∠DHJ
- ∠ECD
(a)
∠DHJ
= 86° - 20°
= 66° (Exterior angle of a triangle)
(b)
∠GCD
= 86° - 36°
= 50° (Exterior angle of a triangle)
∠ECD
= 180° - 50°
= 130° (Angles on a straight line)
Answer(s): (a) 66°; (b) 130°