HJKL is a rhombus, EFL and JFK are straight lines. If JF = FL, ∠FLK = 18° and ∠GJK = 26°, find
- ∠FKL
- ∠GEF
(a)
∠FKL
= 86° - 18°
= 68° (Exterior angle of a triangle)
(b)
∠JEF
= 86° - 26°
= 60° (Exterior angle of a triangle)
∠GEF
= 180° - 60°
= 120° (Angles on a straight line)
Answer(s): (a) 68°; (b) 120°