KLMN is a rhombus, GHN and LHM are straight lines. If LH = HN, ∠HNM = 20° and ∠JLM = 30°, find
- ∠HMN
- ∠JGH
(a)
∠HMN
= 87° - 20°
= 67° (Exterior angle of a triangle)
(b)
∠LGH
= 87° - 30°
= 57° (Exterior angle of a triangle)
∠JGH
= 180° - 57°
= 123° (Angles on a straight line)
Answer(s): (a) 67°; (b) 123°