UVWX is a rhombus, RSX and VSW are straight lines. If VS = SX, ∠SXW = 16° and ∠TVW = 29°, find
- ∠SWX
- ∠TRS
(a)
∠SWX
= 87° - 16°
= 71° (Exterior angle of a triangle)
(b)
∠VRS
= 87° - 29°
= 58° (Exterior angle of a triangle)
∠TRS
= 180° - 58°
= 122° (Angles on a straight line)
Answer(s): (a) 71°; (b) 122°