JKLM is a rhombus, FGM and KGL are straight lines. If KG = GM, ∠GML = 18° and ∠HKL = 31°, find
- ∠GLM
- ∠HFG
(a)
∠GLM
= 84° - 18°
= 66° (Exterior angle of a triangle)
(b)
∠KFG
= 84° - 31°
= 53° (Exterior angle of a triangle)
∠HFG
= 180° - 53°
= 127° (Angles on a straight line)
Answer(s): (a) 66°; (b) 127°