QRST is a rhombus, MNT and RNS are straight lines. If RN = NT, ∠NTS = 18° and ∠PRS = 33°, find
- ∠NST
- ∠PMN
(a)
∠NST
= 82° - 18°
= 64° (Exterior angle of a triangle)
(b)
∠RMN
= 82° - 33°
= 49° (Exterior angle of a triangle)
∠PMN
= 180° - 49°
= 131° (Angles on a straight line)
Answer(s): (a) 64°; (b) 131°