In the figure, QSU and RST are straight lines. SQ = SR and TS = TU. If ∠RQS = 56°, find
- ∠QST
- ∠STU
(a)
∠QST
= 56° + 56°
= 112° (Exterior angle of a triangle)
(b)
∠TSU
= 180° - 112°
= 68° (Angles on a straight line)
∠STU
= 180° - 68° - 68°
= 44° (Isosceles triangle)
Answer(s): (a) 112°; (b) 44°