In the figure, EGJ and FGH are straight lines. GE = GF and HG = HJ. If ∠FEG = 53°, find
- ∠EGH
- ∠GHJ
(a)
∠EGH
= 53° + 53°
= 106° (Exterior angle of a triangle)
(b)
∠HGJ
= 180° - 106°
= 74° (Angles on a straight line)
∠GHJ
= 180° - 74° - 74°
= 32° (Isosceles triangle)
Answer(s): (a) 106°; (b) 32°