In the figure, QSU and RST are straight lines. SQ = SR and TS = TU. If ∠RQS = 54°, find
- ∠QST
- ∠STU
(a)
∠QST
= 54° + 54°
= 108° (Exterior angle of a triangle)
(b)
∠TSU
= 180° - 108°
= 72° (Angles on a straight line)
∠STU
= 180° - 72° - 72°
= 36° (Isosceles triangle)
Answer(s): (a) 108°; (b) 36°