In the figure, VXZ and WXY are straight lines. XV = XW and YX = YZ. If ∠WVX = 56°, find
- ∠VXY
- ∠XYZ
(a)
∠VXY
= 56° + 56°
= 112° (Exterior angle of a triangle)
(b)
∠YXZ
= 180° - 112°
= 68° (Angles on a straight line)
∠XYZ
= 180° - 68° - 68°
= 44° (Isosceles triangle)
Answer(s): (a) 112°; (b) 44°