In the figure, GJL and HJK are straight lines. JG = JH and KJ = KL. If ∠HGJ = 51°, find
- ∠GJK
- ∠JKL
(a)
∠GJK
= 51° + 51°
= 102° (Exterior angle of a triangle)
(b)
∠KJL
= 180° - 102°
= 78° (Angles on a straight line)
∠JKL
= 180° - 78° - 78°
= 24° (Isosceles triangle)
Answer(s): (a) 102°; (b) 24°