In the figure, CEG and DEF are straight lines. EC = ED and FE = FG. If ∠DCE = 59°, find
- ∠CEF
- ∠EFG
(a)
∠CEF
= 59° + 59°
= 118° (Exterior angle of a triangle)
(b)
∠FEG
= 180° - 118°
= 62° (Angles on a straight line)
∠EFG
= 180° - 62° - 62°
= 56° (Isosceles triangle)
Answer(s): (a) 118°; (b) 56°