In the figure, JLN and KLM are straight lines. LJ = LK and ML = MN. If ∠KJL = 58°, find
- ∠JLM
- ∠LMN
(a)
∠JLM
= 58° + 58°
= 116° (Exterior angle of a triangle)
(b)
∠MLN
= 180° - 116°
= 64° (Angles on a straight line)
∠LMN
= 180° - 64° - 64°
= 52° (Isosceles triangle)
Answer(s): (a) 116°; (b) 52°