In the figure, QSU and RST are straight lines. SQ = SR and TS = TU. If ∠RQS = 58°, find
- ∠QST
- ∠STU
(a)
∠QST
= 58° + 58°
= 116° (Exterior angle of a triangle)
(b)
∠TSU
= 180° - 116°
= 64° (Angles on a straight line)
∠STU
= 180° - 64° - 64°
= 52° (Isosceles triangle)
Answer(s): (a) 116°; (b) 52°