In the figure, DFH and EFG are straight lines. FD = FE and GF = GH. If ∠EDF = 59°, find
- ∠DFG
- ∠FGH
(a)
∠DFG
= 59° + 59°
= 118° (Exterior angle of a triangle)
(b)
∠GFH
= 180° - 118°
= 62° (Angles on a straight line)
∠FGH
= 180° - 62° - 62°
= 56° (Isosceles triangle)
Answer(s): (a) 118°; (b) 56°