In the figure, FHK and GHJ are straight lines. HF = HG and JH = JK. If ∠GFH = 58°, find
- ∠FHJ
- ∠HJK
(a)
∠FHJ
= 58° + 58°
= 116° (Exterior angle of a triangle)
(b)
∠JHK
= 180° - 116°
= 64° (Angles on a straight line)
∠HJK
= 180° - 64° - 64°
= 52° (Isosceles triangle)
Answer(s): (a) 116°; (b) 52°