In the figure, PRT and QRS are straight lines. RP = RQ and SR = ST. If ∠QPR = 50°, find
- ∠PRS
- ∠RST
(a)
∠PRS
= 50° + 50°
= 100° (Exterior angle of a triangle)
(b)
∠SRT
= 180° - 100°
= 80° (Angles on a straight line)
∠RST
= 180° - 80° - 80°
= 20° (Isosceles triangle)
Answer(s): (a) 100°; (b) 20°