In the figure, QSU and RST are straight lines. SQ = SR and TS = TU. If ∠RQS = 52°, find
- ∠QST
- ∠STU
(a)
∠QST
= 52° + 52°
= 104° (Exterior angle of a triangle)
(b)
∠TSU
= 180° - 104°
= 76° (Angles on a straight line)
∠STU
= 180° - 76° - 76°
= 28° (Isosceles triangle)
Answer(s): (a) 104°; (b) 28°