In the figure, LNQ and MNP are straight lines. NL = NM and PN = PQ. If ∠MLN = 54°, find
- ∠LNP
- ∠NPQ
(a)
∠LNP
= 54° + 54°
= 108° (Exterior angle of a triangle)
(b)
∠PNQ
= 180° - 108°
= 72° (Angles on a straight line)
∠NPQ
= 180° - 72° - 72°
= 36° (Isosceles triangle)
Answer(s): (a) 108°; (b) 36°