In the figure, MPR and NPQ are straight lines. PM = PN and QP = QR. If ∠NMP = 57°, find
- ∠MPQ
- ∠PQR
(a)
∠MPQ
= 57° + 57°
= 114° (Exterior angle of a triangle)
(b)
∠QPR
= 180° - 114°
= 66° (Angles on a straight line)
∠PQR
= 180° - 66° - 66°
= 48° (Isosceles triangle)
Answer(s): (a) 114°; (b) 48°