In the figure, GJL and HJK are straight lines. JG = JH and KJ = KL. If ∠HGJ = 57°, find
- ∠GJK
- ∠JKL
(a)
∠GJK
= 57° + 57°
= 114° (Exterior angle of a triangle)
(b)
∠KJL
= 180° - 114°
= 66° (Angles on a straight line)
∠JKL
= 180° - 66° - 66°
= 48° (Isosceles triangle)
Answer(s): (a) 114°; (b) 48°