In the figure, NQS and PQR are straight lines. QN = QP and RQ = RS. If ∠PNQ = 51°, find
- ∠NQR
- ∠QRS
(a)
∠NQR
= 51° + 51°
= 102° (Exterior angle of a triangle)
(b)
∠RQS
= 180° - 102°
= 78° (Angles on a straight line)
∠QRS
= 180° - 78° - 78°
= 24° (Isosceles triangle)
Answer(s): (a) 102°; (b) 24°