In the figure, NQS and PQR are straight lines. QN = QP and RQ = RS. If ∠PNQ = 53°, find
- ∠NQR
- ∠QRS
(a)
∠NQR
= 53° + 53°
= 106° (Exterior angle of a triangle)
(b)
∠RQS
= 180° - 106°
= 74° (Angles on a straight line)
∠QRS
= 180° - 74° - 74°
= 32° (Isosceles triangle)
Answer(s): (a) 106°; (b) 32°