In the figure, TVX and UVW are straight lines. VT = VU and WV = WX. If ∠UTV = 54°, find
- ∠TVW
- ∠VWX
(a)
∠TVW
= 54° + 54°
= 108° (Exterior angle of a triangle)
(b)
∠WVX
= 180° - 108°
= 72° (Angles on a straight line)
∠VWX
= 180° - 72° - 72°
= 36° (Isosceles triangle)
Answer(s): (a) 108°; (b) 36°