In the figure, EGJ and FGH are straight lines. GE = GF and HG = HJ. If ∠FEG = 52°, find
- ∠EGH
- ∠GHJ
(a)
∠EGH
= 52° + 52°
= 104° (Exterior angle of a triangle)
(b)
∠HGJ
= 180° - 104°
= 76° (Angles on a straight line)
∠GHJ
= 180° - 76° - 76°
= 28° (Isosceles triangle)
Answer(s): (a) 104°; (b) 28°