In the figure, UWY and VWX are straight lines. WU = WV and XW = XY. If ∠VUW = 56°, find
- ∠UWX
- ∠WXY
(a)
∠UWX
= 56° + 56°
= 112° (Exterior angle of a triangle)
(b)
∠XWY
= 180° - 112°
= 68° (Angles on a straight line)
∠WXY
= 180° - 68° - 68°
= 44° (Isosceles triangle)
Answer(s): (a) 112°; (b) 44°