In the figure, TVX and UVW are straight lines. VT = VU and WV = WX. If ∠UTV = 57°, find
- ∠TVW
- ∠VWX
(a)
∠TVW
= 57° + 57°
= 114° (Exterior angle of a triangle)
(b)
∠WVX
= 180° - 114°
= 66° (Angles on a straight line)
∠VWX
= 180° - 66° - 66°
= 48° (Isosceles triangle)
Answer(s): (a) 114°; (b) 48°