In the figure, QSU and RST are straight lines. SQ = SR and TS = TU. If ∠RQS = 59°, find
- ∠QST
- ∠STU
(a)
∠QST
= 59° + 59°
= 118° (Exterior angle of a triangle)
(b)
∠TSU
= 180° - 118°
= 62° (Angles on a straight line)
∠STU
= 180° - 62° - 62°
= 56° (Isosceles triangle)
Answer(s): (a) 118°; (b) 56°