In the figure, GJL and HJK are straight lines. JG = JH and KJ = KL. If ∠HGJ = 50°, find
- ∠GJK
- ∠JKL
(a)
∠GJK
= 50° + 50°
= 100° (Exterior angle of a triangle)
(b)
∠KJL
= 180° - 100°
= 80° (Angles on a straight line)
∠JKL
= 180° - 80° - 80°
= 20° (Isosceles triangle)
Answer(s): (a) 100°; (b) 20°