In the figure, GJL and HJK are straight lines. JG = JH and KJ = KL. If ∠HGJ = 55°, find
- ∠GJK
- ∠JKL
(a)
∠GJK
= 55° + 55°
= 110° (Exterior angle of a triangle)
(b)
∠KJL
= 180° - 110°
= 70° (Angles on a straight line)
∠JKL
= 180° - 70° - 70°
= 40° (Isosceles triangle)
Answer(s): (a) 110°; (b) 40°