In the figure, VXZ and WXY are straight lines. XV = XW and YX = YZ. If ∠WVX = 51°, find
- ∠VXY
- ∠XYZ
(a)
∠VXY
= 51° + 51°
= 102° (Exterior angle of a triangle)
(b)
∠YXZ
= 180° - 102°
= 78° (Angles on a straight line)
∠XYZ
= 180° - 78° - 78°
= 24° (Isosceles triangle)
Answer(s): (a) 102°; (b) 24°