In the figure, DFH and EFG are straight lines. FD = FE and GF = GH. If ∠EDF = 51°, find
- ∠DFG
- ∠FGH
(a)
∠DFG
= 51° + 51°
= 102° (Exterior angle of a triangle)
(b)
∠GFH
= 180° - 102°
= 78° (Angles on a straight line)
∠FGH
= 180° - 78° - 78°
= 24° (Isosceles triangle)
Answer(s): (a) 102°; (b) 24°