In the figure, FHK and GHJ are straight lines. HF = HG and JH = JK. If ∠GFH = 52°, find
- ∠FHJ
- ∠HJK
(a)
∠FHJ
= 52° + 52°
= 104° (Exterior angle of a triangle)
(b)
∠JHK
= 180° - 104°
= 76° (Angles on a straight line)
∠HJK
= 180° - 76° - 76°
= 28° (Isosceles triangle)
Answer(s): (a) 104°; (b) 28°