In the figure, LNQ and MNP are straight lines. NL = NM and PN = PQ. If ∠MLN = 53°, find
- ∠LNP
- ∠NPQ
(a)
∠LNP
= 53° + 53°
= 106° (Exterior angle of a triangle)
(b)
∠PNQ
= 180° - 106°
= 74° (Angles on a straight line)
∠NPQ
= 180° - 74° - 74°
= 32° (Isosceles triangle)
Answer(s): (a) 106°; (b) 32°