In the figure, VXZ and WXY are straight lines. XV = XW and YX = YZ. If ∠WVX = 58°, find
- ∠VXY
- ∠XYZ
(a)
∠VXY
= 58° + 58°
= 116° (Exterior angle of a triangle)
(b)
∠YXZ
= 180° - 116°
= 64° (Angles on a straight line)
∠XYZ
= 180° - 64° - 64°
= 52° (Isosceles triangle)
Answer(s): (a) 116°; (b) 52°