In the figure, DFH and EFG are straight lines. FD = FE and GF = GH. If ∠EDF = 58°, find
- ∠DFG
- ∠FGH
(a)
∠DFG
= 58° + 58°
= 116° (Exterior angle of a triangle)
(b)
∠GFH
= 180° - 116°
= 64° (Angles on a straight line)
∠FGH
= 180° - 64° - 64°
= 52° (Isosceles triangle)
Answer(s): (a) 116°; (b) 52°