In the figure, VXZ and WXY are straight lines. XV = XW and YX = YZ. If ∠WVX = 59°, find
- ∠VXY
- ∠XYZ
(a)
∠VXY
= 59° + 59°
= 118° (Exterior angle of a triangle)
(b)
∠YXZ
= 180° - 118°
= 62° (Angles on a straight line)
∠XYZ
= 180° - 62° - 62°
= 56° (Isosceles triangle)
Answer(s): (a) 118°; (b) 56°