In the figure, HKM and JKL are straight lines. KH = KJ and LK = LM. If ∠JHK = 58°, find
- ∠HKL
- ∠KLM
(a)
∠HKL
= 58° + 58°
= 116° (Exterior angle of a triangle)
(b)
∠LKM
= 180° - 116°
= 64° (Angles on a straight line)
∠KLM
= 180° - 64° - 64°
= 52° (Isosceles triangle)
Answer(s): (a) 116°; (b) 52°