In the figure, JLN and KLM are straight lines. LJ = LK and ML = MN. If ∠KJL = 53°, find
- ∠JLM
- ∠LMN
(a)
∠JLM
= 53° + 53°
= 106° (Exterior angle of a triangle)
(b)
∠MLN
= 180° - 106°
= 74° (Angles on a straight line)
∠LMN
= 180° - 74° - 74°
= 32° (Isosceles triangle)
Answer(s): (a) 106°; (b) 32°