In the figure, NQS and PQR are straight lines. QN = QP and RQ = RS. If ∠PNQ = 58°, find
- ∠NQR
- ∠QRS
(a)
∠NQR
= 58° + 58°
= 116° (Exterior angle of a triangle)
(b)
∠RQS
= 180° - 116°
= 64° (Angles on a straight line)
∠QRS
= 180° - 64° - 64°
= 52° (Isosceles triangle)
Answer(s): (a) 116°; (b) 52°