In the figure, UWY and VWX are straight lines. WU = WV and XW = XY. If ∠VUW = 52°, find
- ∠UWX
- ∠WXY
(a)
∠UWX
= 52° + 52°
= 104° (Exterior angle of a triangle)
(b)
∠XWY
= 180° - 104°
= 76° (Angles on a straight line)
∠WXY
= 180° - 76° - 76°
= 28° (Isosceles triangle)
Answer(s): (a) 104°; (b) 28°