In the figure, CEG and DEF are straight lines. EC = ED and FE = FG. If ∠DCE = 56°, find
- ∠CEF
- ∠EFG
(a)
∠CEF
= 56° + 56°
= 112° (Exterior angle of a triangle)
(b)
∠FEG
= 180° - 112°
= 68° (Angles on a straight line)
∠EFG
= 180° - 68° - 68°
= 44° (Isosceles triangle)
Answer(s): (a) 112°; (b) 44°