In the figure, EGJ and FGH are straight lines. GE = GF and HG = HJ. If ∠FEG = 51°, find
- ∠EGH
- ∠GHJ
(a)
∠EGH
= 51° + 51°
= 102° (Exterior angle of a triangle)
(b)
∠HGJ
= 180° - 102°
= 78° (Angles on a straight line)
∠GHJ
= 180° - 78° - 78°
= 24° (Isosceles triangle)
Answer(s): (a) 102°; (b) 24°