In the figure, TVX and UVW are straight lines. VT = VU and WV = WX. If ∠UTV = 52°, find
- ∠TVW
- ∠VWX
(a)
∠TVW
= 52° + 52°
= 104° (Exterior angle of a triangle)
(b)
∠WVX
= 180° - 104°
= 76° (Angles on a straight line)
∠VWX
= 180° - 76° - 76°
= 28° (Isosceles triangle)
Answer(s): (a) 104°; (b) 28°