In the figure, VXZ and WXY are straight lines. XV = XW and YX = YZ. If ∠WVX = 54°, find
- ∠VXY
- ∠XYZ
(a)
∠VXY
= 54° + 54°
= 108° (Exterior angle of a triangle)
(b)
∠YXZ
= 180° - 108°
= 72° (Angles on a straight line)
∠XYZ
= 180° - 72° - 72°
= 36° (Isosceles triangle)
Answer(s): (a) 108°; (b) 36°