In the figure, VXZ and WXY are straight lines. XV = XW and YX = YZ. If ∠WVX = 52°, find
- ∠VXY
- ∠XYZ
(a)
∠VXY
= 52° + 52°
= 104° (Exterior angle of a triangle)
(b)
∠YXZ
= 180° - 104°
= 76° (Angles on a straight line)
∠XYZ
= 180° - 76° - 76°
= 28° (Isosceles triangle)
Answer(s): (a) 104°; (b) 28°