In the figure, PRT and QRS are straight lines. RP = RQ and SR = ST. If ∠QPR = 60°, find
- ∠PRS
- ∠RST
(a)
∠PRS
= 60° + 60°
= 120° (Exterior angle of a triangle)
(b)
∠SRT
= 180° - 120°
= 60° (Angles on a straight line)
∠RST
= 180° - 60° - 60°
= 60° (Isosceles triangle)
Answer(s): (a) 120°; (b) 60°